坚度数据导出说明

一.导出方案

1.1 选择数据库-->数据右键-->任务-->导入数据

1.2 选择“下一步”

1.3 选择数据源

1.4 选择导出目标

1.5 点击“浏览”选择文件保存类型

1.6 选好了直接下一步

1.7 选择要导出的表或者视图

1.8 输入导出语句

sql语句输入导出脚本的相关语句即可
会员导出脚本
select cname as 会员姓名, ptelephone as '联系电话', case sex when 1 then '男' when 2 then '女' else '男' end as '性别', borndate as '公历生日', HYLX as '会员等级', case state when 1 then '启用' when 2 then '停用' when 6 then '挂失' else '未知' end as '卡状态', CustomNO as '会员卡号', isnull(syje,0) as '剩余金额', applydate as '建卡时间', enddate as '有效期' from ( select a.borndate, a.CustomNO,a.IDCardNo,a.HYLXID,a.cname,a.password, a.passbookid,a.marry,a.ptelephone,a.addr,a.ppostcode,a.companyname, a.companyaddr,a.ctelephone,a.faxno,a.email,a.cpostcode,a.proposer,a.givedate, a.startdate,a.enddate,a.saveamot,a.Presentamot,a.applyDate,a.fmwhere,a.HYJF,a.zpimage, a.billtotal,a.updateDate,a.updateFlag,a.sync_stat, a.xf_psw,a.DANHAO,a.ImageFileName ,a.rowguid,a.storeid, a.authtelr, a.vselfDef4,a.vselfDef5,a.vselfDef2,a.vselfDef3, a.cardType,a.maketelr , (case when a.sex not in (0,1,2) then 0 else a.sex end) sex, (case when a.state not in (1,2,3,4,5,6,7,8) then -1 else a.state end) state, (case when (isnull(iselfDef1,0) & 1)=1 then '是' else '否' end) bdxs, b.syjf,d.zjf, b.syje,b.zhzh,b.posje,b.roomje,a.memo, e.HYLX,e.HYZK from lr_hy_hyzl a left outer join (select customno, round(isnull(sum(jf),0),2) as syjf, round(isnull(sum(je),0),2) as syje, round(isnull(sum(zsje),0),2) as zhzh, round(isnull(sum(posje),0),2) as posje, round(isnull(sum(roomje),0),2) as roomje from lr_hy_core where (actions in (1, 2, 4)) group by customno) b on a.customno = b.customno left outer join (select customno, round(isnull(sum(jf),0),2) as zjf from lr_hy_core where (actions in (4,7)) group by customno) d on a.customno = d.customno left join lr_hy_hylx e on e.hylxid=a.hylxid ) f where 1=1 order by f.applyDate desc
公关导出脚本
select (select cateName from [dbo].[prd_cate] where cateIds=prd_person.cateIds) '类别', (select levelName from [dbo].[prd_level] where levelIds=prd_person.levelIds) '级别', personName as '姓名', personStage as '艺名', personCode as '代号', isnull(cardNo,'') as '卡号', isnull(tel,'') as '电话', isnull(idenNo,'') as '身份证', personFee as '余额' from prd_person where 1=1 and isnull(personIsStop,0)=0

1.9 下一步

1.10 “完成”

1.11 导出成功

  
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